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An usher seats moviegoers into rows so that each row holds exactly 8 people with none left over. Which of the following could be the total number of moviegoers seated?
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Correct answer
E
Exact rows of 8 force the total to be a multiple of 8, and 8 = 2 × 2 × 2 demands three factors of 2, a stricter test than looking even. Divide each candidate by 8: 72 ÷ 8 = 9 exactly, so 72 works, choice (E).
The others all leave remainders: 60 ÷ 8 = 7.5, 66 ÷ 8 = 8.25, 68 ÷ 8 = 8.5, 70 ÷ 8 = 8.75. The modal trap is (A) 60, which is divisible by 4 and so survives a casual halving check twice, but not a third time. (B) 66, (C) 68, and (D) 70 are merely even. For a composite divisor like 8, count the full prime power before accepting: 72.
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