Data InsightsMulti-Source Reasoning

Free GMAT Multi-Source Reasoning Practice Question

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An amateur astronomy club received a small grant to image a list of deep-sky targets over one season. Each target can be imaged only on a night that satisfies several constraints at once, and the club must decide which targets are imageable from its site this season. For a target to be imageable on a given night, all of the following must hold:

Altitude: the target must rise at least 30 degrees above the horizon (low targets are blurred by atmosphere). Moon: the night must be a dark night (Moon illumination at most 20 percent) for faint targets; bright targets (magnitude brighter than 6.0) tolerate any Moon. Window: the target's nightly observable window must be at least 90 minutes long to collect enough exposure.

The club images at most one target per usable night and has 24 usable nights this season.

The club wants to complete as many targets as possible this season. A target is completed only if it is imaged on enough qualifying nights, at least 3 dark, high-altitude nights for a faint target, or 1 qualifying night for a bright target, and the club has 24 usable nights, imaging at most one target per night. Using the sources, what is the largest number of targets the club can complete this season?

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Answer & Explanation

Correct answer

C

Two things gate completion: a target must be imageable, and the club must have enough qualifying nights. The imageable set is Nebula-A, Nebula-D, Cluster-E, Galaxy-F (Cluster-B and Galaxy-C are not imageable, capping the answer below 5).

Each imageable target has enough of its own qualifying nights: Nebula-A (faint, needs 3, has 9), Nebula-D (needs 3, has 6), Galaxy-F (needs 3, has 5), Cluster-E (bright, needs 1, has 16).

Completing all four costs 3 + 3 + 3 + 1 = 10 imaging-nights, well within 24, so the club can complete all four.