One statement builds a per-sheet ratio, one weights a price by skating volume, and one tests a co-occurrence no row supports.
Skater-hours per sheet is weekly skater-hours divided by ice sheets: Arctic 12, Blizzard 8, Crystal 15, Drift 9, Frost 8.
Statement 1 - No. The rink with the most skater-hours is Blizzard at 72,000, but across 9 sheets that is only 8 per sheet, tied for the lowest; the densest is Crystal at 15 with just 2 sheets. So the busiest rink is not the most productive per sheet, and the statement is false. The trap is to assume the busiest rink leads on every measure.
Statement 2 - Yes. The simple average of the five session prices is (16 + 11 + 22 + 14 + 19) / 5 = $16.40. Weighting each price by the rink's skater-hours gives (768 + 792 + 660 + 756 + 760) / 244 = 3,736 / 244 = $15.31. The volume-weighted figure is lower, so the statement is true. The reason is that the busiest rink, Blizzard with 72,000 skater-hours, charges the lowest price of $11, so it carries the most weight and pulls the average down. The trap is to average the five prices and stop.
Statement 3 - No. The most skater-hours is Blizzard at 72,000, but the most staff is Drift at 60; Blizzard has 55. The two leaders are different rinks, so the statement is false. The trap is to assume the busiest rink must employ the most people.
The lesson: a per-sheet figure is built not read, an average weighted by volume can fall below the simple mean, and one rink need not lead on two measures at once. Correct answers: No / Yes / No.