Data InsightsGraphs & Tables

Free GMAT Graphs & Tables Practice Question

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Five kennels in rows; columns: annual boardings, runs, floor area (square feet), nightly price (dollars). Sortable.
Kennel	Annual boardings	Kennels (runs)	Floor area (sq ft)	Price ($/night)
Pawsabode	7,200	24	9,000	40
Kibble	10,800	40	13,500	32
Snout	4,500	16	6,000	56
Whisker	6,000	20	7,500	48
Wagtail	5,400	18	6,500	64

The table shows five pet boarding kennels: annual boardings, the number of runs, the floor area in square feet, and the nightly price. The table can be sorted by any column. For each statement, select Yes if it must be true based only on the data shown; otherwise select No.

(1) When the kennels are sorted by annual boardings from highest to lowest, Wagtail appears in the bottom row: . (2) The kennel with the most annual boardings also has the most boardings per run: . (3) From the data shown, it can be determined which kennel takes in the most annual revenue per square foot of floor space: .

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Answer & Explanation

Correct answer

1: No · 2: No · 3: Yes

One statement hinges on actually re-sorting, one builds a per-run ratio, and one asks only whether a per-square-foot figure can be determined.

Statement 1: No. Wagtail is the last row as the table is printed, which is the bait. But the statement asks about the order after sorting by annual boardings from highest to lowest, and that order is Kibble 10,800, Pawsabode 7,200, Whisker 6,000, Wagtail 5,400, Snout 4,500. The bottom row of that sort is Snout, which boards the fewest, not Wagtail. So the statement is false. The trap is to trust the printed order instead of actually re-sorting.

Statement 2: No. Boardings per run is annual boardings ÷ runs: Pawsabode 300, Kibble 270, Snout 281.25, Whisker 300, Wagtail 300. The kennel with the most boardings is Kibble at 10,800, but across 40 runs that is only 270 per run, the lowest; three kennels reach 300 with fewer runs. So the busiest kennel is not the most productive per run, and the statement is false. The trap is to assume the kennel with the most boardings works its runs hardest.

Statement 3: Yes. The table prints no revenue-per-square-foot column, but it gives boardings, the nightly price, and the area, so the figure is computable: boardings × price ÷ area gives Pawsabode $32.00, Kibble $25.60, Snout $42.00, Whisker $38.40, Wagtail $53.17. The highest is Wagtail, so the answer can be determined. The statement asks only whether it can be determined, and it can. The trap is to answer No because no such column is shown, or to pick Kibble for its biggest volume; the small high-price Wagtail earns the most per square foot.

The lesson: a position claim demands a real re-sort, a per-run figure is built not read, and anything you can compute from the given columns is determinable. Correct answers: No / No / Yes.